If the steel has a tensile reduction value of 10 percent, divide 50 by that value:50/10 = 5. Next, subtract 1 from that answer:5 1 = 4. Now, multiply that answer by the plate thickness. If the material is 0.5 in. thick:4 × 0.5 = 2. So in this case, the minimum inside bend radius is 2 times the material thickness.
Chapter 1 stress and strain - SlideShareJun 19, 2016 · As illustrated, the offset yield stress is determine by; Drawing a straight line that best fits the data in initial (linear) portion of the stress-strain diagram Second line is then drawn parallel to the original line but offset by specified amount of strain The intersection of this second line with the stress-strain curve determine the offset yield stress. Commonly used offset value is 0.002/0.2% 32 26. Brittle material
The weight of the new orthotropic steel plate deck, Yield Str, Fy = 182,600 psi (160,000 psi min) (4.0% min) Main Cable bands are located every 50 feet along the main cables and the vertical suspender ropes are hung from the cable bands. Following the addition of the lower lateral bracing system in 1953 and 1954, it was found that the
FABRICATION AND ERECTION OF STRUCTURAL 2.2.2 Flame Cutting or Burning In this method, the steel is heated locally by a pressurised mixture of oxygen and a combustible gas such as propane, which passes through a ring of small holes in a cutting nozzle. The heat is focussed on to a very narrow band and the steel melts at 15000 C
Introduction to Tensile Testing - ASM International0.002 or 0.2%. The yield strength is the stress at which this line intersects the stress-strain curve (Fig. 6). The rationale is that if the material had been loaded to this stress and then unloaded, the unloading path would have been along this off-set line and would have resulted in a plastic strain of e 0.2
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Press Brake Tonnage Chart from American Machine ToolsAnswer:Use a 2-1/2 inch wide bottom die. 11.5 tons/foot x 10 feet = 115 tons. Question:How many tons is required for a brake press machine to bend 10 feet of 1/4 inch thick stainless steel using using a 2 1/2 inch wide bottom die? Answer:115 tons x 90ksi divided by 60ksi = 177.5 tons.
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Chemical FormulaKey PropertiesMechanical PropertiesGrade Specification ComparisonCorrosion ResistanceHeat ResistanceHeat TreatmentWeldingMachiningDual CertificationApplicationsFe, <0.03% C, 16-18.5% Cr, 10-14% Ni, 2-3% Mo, <2% Mn, <1% Si, <0.045% P, <0.03% SGrade 316 is the standard molybdenum-bearing grade, second in importance to 304 amongst the austenitic stainless steels. The molybdenum gives 316 better overall corrosion resistant properties than Grade 304, particularly higher resistance to pitting and crevice corrosion in chloride environments. It has excellent forming and welding characteristics. It is readily brake or roll formed into a variety of parts forCHAPTER 6. WELDED CONNECTIONS 6.1 Step I. Assume material properties Assume 36 ksi steel for designing the member and the gusset plates. Assume E70XX electrode for the fillet welds. Step II. Design the tension member From Table 3-7 on page 3-32 of the AISC manual, select 2L 5 x 3½ x 1/2 made from 36 ksi steel with yield strength = 259 kips and fracture strength = 261 kips.
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Tonnage Calculator & Bend Allowance Calculator ToolsDISCLAIMER:Actual bending force is affected by many factors such as friction between the material and the die, material thickness, material strength variations, rolling direction of the steel, work hardening and other parameters. This estimator calculates a force representative of the pressbrake requirement for air bending. Sizing of a machine or available die width should allow for up to 20%
DISCLAIMER:Actual bending force is affected by many factors such as friction between the material and the die, material thickness, material strength variations, rolling direction of the steel, work hardening and other parameters. This estimator calculates a force representative of the pressbrake requirement for air bending. Sizing of a machine or available die width should allow for up to 20%